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Post by rockpickerforever on Jun 13, 2016 17:07:51 GMT -5
NEW CONTENT ON PAGE THREE.
Hadn't been for a while, so decided to go to the swapmeet on Sunday. We call it a swapmeet here, "Flea Market" is more of a back east thing. Besides, I'm not in the market for fleas right now, lol.
Picked this up for the huge sum of $5. Needs a pump. I tried a pump that I had, but it (66 GPH) wouldn't lift that heavy rock.
An 8" sphere of onyx (?) has got to be worth at least $5. (Taking a page out of jamesp 's book. Sphere is much larger than my head!))
And then, from anbother seller, I bought a bunch of slabs, for the princely total of$3. Yes, all of them for $3. Mostly agates, a thunderegg, sliced, and a halved T-egg/geode with polished face. The golden slab at bottom center is also polished, on both sides.
Dry
Wet
The halved t-egg/geode
He either didn't have good equipment, or a clue what he was doing. Bad cuts on the three slabs from this rock. (But not on all of them.)
This one is interesting. Just a slice.
Looks like some Gary Green jasper.
This one polished on both sides.
It's got some turtling in it, don't know if I caught that or not.
The t-egg slice.
Agate with quartz.
An unknown
Close up.
A small section.
Unfortunately, when you steal pay so little for them, they don't come with names. That's okay.
That's it, thanks for looking. Jean
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Sabre52
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Me and my gal, Rosie
Member since August 2005
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Post by Sabre52 on Jun 13, 2016 18:07:51 GMT -5
Boy that strange t-egg slice with the greenish exterior looks almost like a cut off a Templeton Biconid. Very odd looking specimen...Mel
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jamesp
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Post by jamesp on Jun 13, 2016 18:33:30 GMT -5
Sphere white large and pure. Looks sounds like my brain. I must ask Mel what a Biconid is. Sexy word.
Can't believe that big sphere was had for only $5.
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wampidytoo
has rocks in the head
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Post by wampidytoo on Jun 13, 2016 18:53:32 GMT -5
You and your deals Jean. Every time. The stars must be aligned for you.
I have slabs of carnelian that look exactly like the polished slab. Gave one to Susan at Q and she did not notice the turtle back until she got home. Back lit they are awesome. The stone that I slabbed was given to me by someone in Montana who said he bought a ton of it but I do not know where he got it. Jim
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Post by rockjunquie on Jun 13, 2016 20:08:37 GMT -5
Yup, flea markets out here, but I got my first bike (with a banana seat and a sissy bar) at a swap meet. You always find something cool. I like the sphere. I wonder what it would look like with a light under it.
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quartz
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breakin' rocks in the hot sun
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Post by quartz on Jun 13, 2016 23:49:39 GMT -5
Such a deal you fell into, nice mtl. all. Now for the bigger pump.
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Deleted
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Post by Deleted on Jun 14, 2016 0:03:55 GMT -5
Sweet!
A magnetically coupled aquarium pump is not likely to provide enough head to float that ball.
Weight of ball divided by square inches of surface area will say psi you need.
What does it mean, "turtling"?
I too am in awe of your many and various outstanding flea market scores.
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Post by Garage Rocker on Jun 14, 2016 0:09:18 GMT -5
Nice finds! I used to take an annual golf trip to Santee (South Carolina). I'm pretty sure they'd be flea markets down that way.
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Fossilman
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Post by Fossilman on Jun 14, 2016 9:19:52 GMT -5
SCORE! Nice Brazilian (polished) and that sliced thunderegg is a Richardson Ranch "Blue Bed" egg... That sphere is killer cool!
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wampidytoo
has rocks in the head
Add 5016 to my post count.
Member since June 2013
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Post by wampidytoo on Jun 14, 2016 10:04:12 GMT -5
Sweet! A magnetically coupled aquarium pump is not likely to provide enough head to float that ball. Weight of ball divided by square inches of surface area will say psi you need. What does it mean, "turtling"? I too am in awe of your many and various outstanding flea market scores. The lines you see radiating out from the center are called turtling which are hard to pick up with a camera but easy to see in hand. I checked some photos I have and Jean's camera picked them up better than mine. Jim
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Post by rockpickerforever on Jun 14, 2016 10:45:49 GMT -5
Sweet! A magnetically coupled aquarium pump is not likely to provide enough head to float that ball. Weight of ball divided by square inches of surface area will say psi you need. What does it mean, "turtling"? I too am in awe of your many and various outstanding flea market scores.
Thank you, Scott. I do seem to have the knack (right place, right time) for deals. Someone started to chastise me for purchasing it, until I told him what I paid for it, lol.
Great information and photos of Turtle-back agates at this link: www.spiritrockshop.com/Special_Slabs.html
I have no affiliation with this site, but he sure has some nice stuff!
Now I have to put on my thinking cap and do some math. The sphere weighs 25.2 lbs. I know it is ~ 8" diameter, but I'll use some calipers to get a more exact measurement. I'm only gonna do this once!
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jamesp
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Post by jamesp on Jun 14, 2016 10:58:51 GMT -5
Scott is right. A low flow/higher head pump should get it done. I was having to do a calculation on a slice of a sphere. somewhat related. Maybe I can find or derive the formula for-'the surface area of a dome'. That would be the way to say it I believe. OK, here we go static.monolithic.com/pdfs/formulas.pdfNot so bad. Surface area = 3.14(h squared + radius squared) so if the cup is 2 inches deep and the width at the top is 5 inches S = 3.14(2X2 + 2.5x2.5) = 3.14(4 + 6.25) = 32 sq. in. I believe that is correct.
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Post by rockpickerforever on Jun 14, 2016 11:08:15 GMT -5
Will measure the exact diameter of the sphere, then calculate the surface area. Then Scott says I take "Weight of ball divided by square inches of surface area will say psi you need". Simple, no?
If I really wanted exactamundo, I could get a more precise weight by finding the volume of said sphere, and the density of it. Just used digital bathroom scale (Jean + rock - Jean without rock = 25.2 lbs) to get that.
I can do this (mom was a math major, Dad an engineer)! Just have a few things to take care of first.
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Deleted
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Post by Deleted on Jun 14, 2016 11:10:31 GMT -5
The water is only pushing on a small portion of the sphere. It is THOSE square inches you need. Not the entire ball
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jamesp
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Post by jamesp on Jun 14, 2016 11:15:42 GMT -5
Will measure the exact diameter of the sphere, then calculate the surface area. Then Scott says I take "Weight of ball divided by square inches of surface area will say psi you need". Simple, no? If I really wanted exactamundo, I could get a more precise weight by finding the volume of said sphere, and the density of it. Just used digital bathroom scale (Jean + rock - Jean without rock = 25.2 lbs) to get that. I can do this (mom was a math major, Dad an engineer)! Just have a few things to take care of first. Yes, weight of ball divided by area. But pump probably should a bit more powerful to overcome imbalance. Call my client, they got those type sphere pump fountains. 404-235-0739 www.atlantawatergardens.com/products/pond-supplies/
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jamesp
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Post by jamesp on Jun 14, 2016 11:17:30 GMT -5
The water is only pushing on a small portion of the sphere. It is THOSE square inches you need. Not the entire ball Yes, above calculation for surface area of a dome segment of a whole sphere. The area of the saddle.
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Post by rockpickerforever on Jun 14, 2016 11:19:34 GMT -5
The water is only pushing on a small portion of the sphere. It is THOSE square inches you need. Not the entire ball Righto! Thank you, Scott. I will say the el cheapo Harbor Freight pump did lift the ball enough so it could be turned by hnd (with some effort), but no way it would have turned on its own.
Let me log off and get the trash put out, will get to it shortly...
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Deleted
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Post by Deleted on Jun 14, 2016 11:20:35 GMT -5
The water is only pushing on a small portion of the sphere. It is THOSE square inches you need. Not the entire ball Yes, above calculation for surface area of a dome segment of a whole sphere. The area of the saddle. Perfect i was addressing without tag lol For pumps rated by head pressure, one can use 2feet of head pressure per pound of pressure
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jamesp
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Post by jamesp on Jun 14, 2016 13:02:28 GMT -5
2.316396487784235948 feet/psi
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Post by rockpickerforever on Jun 14, 2016 13:14:36 GMT -5
Not what I came up with, James. Not saying you are wrong, just that we came up with different answers, lol.
Then found a website where I only had to plug in two numbers - sphere radius and cap height. www.1728.org/sphere.htm When
R= 3.9375 (is 7 7/8 diameter, not 8) h = 1
25.2 (weight of sphere in lbs) divided by 24.74 (surface area of spherical cap in sq inches) = 1.0186 PSI??
That's not very much. What am I missing??
Thank you for all your help, guys!!
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